5(a+2)=7[a-(10-a)]

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Solution for 5(a+2)=7[a-(10-a)] equation:


Simplifying
5(a + 2) = 7[a + -1(10 + -1a)]

Reorder the terms:
5(2 + a) = 7[a + -1(10 + -1a)]
(2 * 5 + a * 5) = 7[a + -1(10 + -1a)]
(10 + 5a) = 7[a + -1(10 + -1a)]
10 + 5a = 7[a + (10 * -1 + -1a * -1)]
10 + 5a = 7[a + (-10 + 1a)]

Reorder the terms:
10 + 5a = 7[-10 + a + 1a]

Combine like terms: a + 1a = 2a
10 + 5a = 7[-10 + 2a]
10 + 5a = [-10 * 7 + 2a * 7]
10 + 5a = [-70 + 14a]

Solving
10 + 5a = -70 + 14a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-14a' to each side of the equation.
10 + 5a + -14a = -70 + 14a + -14a

Combine like terms: 5a + -14a = -9a
10 + -9a = -70 + 14a + -14a

Combine like terms: 14a + -14a = 0
10 + -9a = -70 + 0
10 + -9a = -70

Add '-10' to each side of the equation.
10 + -10 + -9a = -70 + -10

Combine like terms: 10 + -10 = 0
0 + -9a = -70 + -10
-9a = -70 + -10

Combine like terms: -70 + -10 = -80
-9a = -80

Divide each side by '-9'.
a = 8.888888889

Simplifying
a = 8.888888889

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